How to create a Date (or DateTime) from year month day or big decimal in Pega?
E.g. I have 3 integers, 2022, 10, 03, I need create a Date 2022Oct03, how to do it?
Another option, I get a BigDecimal from function date(year, month, day), then how can I create a Date (or DateTime) from the BigDecimal?
Pls note I would like to use Pega OOTB functions only, instead of write Java codes.
Hi @MaxonL16591286 , do you really want “Oct” in your final result or is it just for explaining? Asking this because having “Oct” will make it a non pega date.
To simply achieve date from string you can use: @DateTime.addToDate (“Param.YourDate”,“”,“”,“”,“”) just make sure to concatenate the three integers into a param and pass the param onto your function.
kalls4
(Sricharan Vachaspathi Kallagunta)
August 16, 2023, 12:39pm
3
@MaxonL16591286
Hello,
Can you try the following:
@DateTime.FormatDateTime (@addToDate (“19700101”,@round (@date (2022,10,03)),‘0’,‘0’,‘0’),YYYYMMMdd,“GMT”,null)
@date (2022,10,03) - 19268.0
@round (@date (2022,10,03)) - 19268
@addToDate (“19700101”,@round (@date (2022,10,03)),‘0’,‘0’,‘0’) - 20221003T000000.000 GMT
@DateTime.FormatDateTime (@addToDate (“19700101”,@round (@date (2022,10,03)),‘0’,‘0’,‘0’),YYYYMMMdd,“GMT”,null) - 2022Oct03
@SaurabhG7134
“Oct” is it just for explaining, i need build a day into a property of type Date or DateTime in Pega, with my specified year, month day.
addToDate function is to add days based on an existing date.
I’d like to build a day myself from scratch.
@kalls4
many thanks. Let me try. As I need a value put in Date / DateTime property, no need format, so I will test below only:
@addToDate (“19700101”,@round (@date (2022,10,03)),‘0’,‘0’,‘0’)